3[x+2]=10[x-5]

Solution for 3[x+2]=10[x-5] equation:

Simplifying
3[x + 2] = 10[x + -5]

Reorder the terms:
3[2 + x] = 10[x + -5]
[2 * 3 + x * 3] = 10[x + -5]
[6 + 3x] = 10[x + -5]

Reorder the terms:
6 + 3x = 10[-5 + x]
6 + 3x = [-5 * 10 + x * 10]
6 + 3x = [-50 + 10x]

Solving
6 + 3x = -50 + 10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10x' to each side of the equation.
6 + 3x + -10x = -50 + 10x + -10x

Combine like terms: 3x + -10x = -7x
6 + -7x = -50 + 10x + -10x

Combine like terms: 10x + -10x = 0
6 + -7x = -50 + 0
6 + -7x = -50

Add '-6' to each side of the equation.
6 + -6 + -7x = -50 + -6

Combine like terms: 6 + -6 = 0
0 + -7x = -50 + -6
-7x = -50 + -6

Combine like terms: -50 + -6 = -56
-7x = -56

Divide each side by '-7'.
x = 8

Simplifying
x = 8